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C. M. Consulting
P.O. Box 407
Odell, Oregon 97044
United States
Phone: 5413527942
Fax: 5413527943
cmconsulting@hotmail.com
CD Road Equipment S & S
313 Cowie Crescent Swift Current, SK S9H 4W1
Canada
Phone: 3067411333 Fax: 306 992 0789
dougbleackley@sasktel.net

C. M. CONSULTING
A Division of Cliff Mansfield Incorporated

Specializing
in New & Used Asphalt Plants, Sales, Parts, Service, Repairs, DEQ and Mix Design Compliance and Complete Consulting Services.
USEFUL NOTES & FORMULAS
GENERAL
A plant loses about 3% of its production rate per 1000 feet of elevation due to the thinning of the air.
Plants are designed to remove 5% moisture. The higher the moisture, the lower the production rate.
To Calculate A Batch Plant's Rate Of Production:
 Choose a weigh point on your aggregate scale (must be in a bin you are waiting on so that the pointer is rising slowly)
 With a stopwatch, determine the amount of time it takes the scales to return to this point  Time in seconds=(s)
 Divide (s) into the number of seconds per hour (3600)
 Multiply that answer by the average batch size (b)
 Assume the following: s=45seconds, b=5000# or 2.5 tons
 EXAMPLE: 3600 div. 45= 80 batches per hour
 80x 2.5 = 200tph
To Calculate A Drum Plant's Rate Of Production:
 Multiply the aggregate tons per hour (x) times 100% minus the moisture content (y)
 Add the oil tons per hour (z)
 Assume the following: x= 209, y= 4.3%, z= 11.76
 EXAMPLE: 209x .957= 200.01
 200.01+ 11.76= 211.77tph
To Convert Horsepower To KW:
 Multiply horsepower (h) by .7457
 Assume the following: h= 350hp
 EXAMPLE: 350x .7457= 261 KW
To Calculate The Length Of A Slat Conveyor At A 45 Degree Angle:
 Measure height (h), multiply by 1.41416
 Assume the following: h= 65'
 EXAMPLE: 65x 1.41416= 91.9204 feet long slat at 45 degrees
To Calculate The Speed In FeetPerMinute Of A Slat Conveyor, The Following Information Is Needed:
 Motor RPM (rpm)
 Motor sheave size (ms)
 Driven sheave size (ds)
 Gear box ratio (gbr)
 Head sprocket size (hs)
 Assume the following: Rpm= 1755, ms= 8", ds= 14", gbr= 25.13 to 1 and hs= 9"
 Calculate the sheave ratio, i.e.: 8" drive, 14" driven
 Multiply motor speed by the answer = input RPM
 Input RPM divided by gear box ratio x diameter of head pulley x .2618= slat speed in Feet Per Minute
 EXAMPLE: 8 divided by 14 = .571 x 1755 = 1002.86 input rpm div. 25.13 gbr = 39.91 head shaft rpm
39.91 x 9 = 359.19 x .2618 = 94.04 FPM
.
ASPHALT OIL
To Find Asphalt % By Total Mix:
 Add oil to aggregate then divide oil by total of the two
 Assume the following: 250 tons aggregate used, 15 tons oil used
 Example: 250agg + 15oil = 265 15 div 265 = .0566% oil by total
To Calculate Where You Should Be Running With A Known Aggregate Tph:
 TPH of dry aggregate x % of oil, div. 100% of oil = oil tph
 Assume the following: 70tph aggregate (dry), 5.4% oil
 Example: 100%  5.4% = 94.6 70 tph x 5.4% = 378 div 94.6 = 3.99 tph of oil
To Find The Number Of Gallons Delivered On A Particular BILL OF LADING:
 Net weight in pounds (x), divide 8.328 (pounds per gallon of water, which has a specific gravity of 1.0) = y
 Divide y by the specific gravity (z) listed on the delivery ticket for the oil you are using
 Assume the following: x= 66,920, z= 1.0273
 Example: 66,920 divide 8.328= 8,035.54 (y)
 8,035.54 divide 1.0273 (z)= 7,822 gallons at 60 degrees Fahrenheit
To Find Asphalt Gallons Per Ton:
 Look up AC pounds per gallon at the oil's temperature (x)
 Divide that number into 2000
 Assume the following: x = 7.81
 Example: 2000 div. 7.81 = 256.08 gallons AC per ton at the chosen temperature
To Convert Gallons Of Oil To Tons:
 Look up AC pounds per gallon at the oil's temperature (x)
 Multiply that number by number of gallons
 Divide that number by 2000
 Assume the following: x = 7.81
 Example: 7.81 ppg x 25,000 gals = 195,250# div
 2000 = 97.625 tons of oil at (x) temperature
To Find Out How Many Tons Of Oil Are In An AC Tank:
 Check oil temperature (t)
 Measure liquid, convert inches to gallons (g)
 Find temperature on compensation chart and get conversation factor (f)
 Read oil poundspergallon* at 60 degrees (p)
 Assume: t= 325 degrees
 g= 12,834 gallons, f= .9105, p= 8.456
 Example: 8.456 x .9105= 7.699ppg at 325 degrees
 7.699ppg x 12,834gals = 98,811.37 pounds
 98,811.37 # divide 2,000 = 49.41tons of oil
To Figure Out How Much Mix You Can Make With A Given Quantity Of Oil:
* Actual ppg of water
To Find The US Gallons Capacity Of A Cylindrical Tank:
 Measure the diameter (d) and the length (l)
 Square the diameter, multiply by length, then multiply by .0034
 Assume: d= 95", l= 337"
 Example: 95x 95x 337x .0034= 10,341 gallons
.
BAGHOUSE
It requires approximately 165
CFM of air to produce 1 ton of hot mix.
To Find The Correct Baghouse Size For A Particular Drum:
 Radius x radius x 3.142 (pi) x *1000= CFM required
 Example: Assume a 9 foot drum. 4.5 x 4.5 = 20.25 x 3.142 = 63.6255 x 1000 = 63,625.5 CFM
 This drum would require a 65,000 CFM baghouse
*1000 equals the air velocity through the dryer/mixer.
This figure is usually down around 750 to 850fpm, but using 1000fpm give
a little bit of oversizing which is a good thing since you don't want the
air flow through the baghouse to limit production rates.
To Find The Square Feet Of Cloth In A Particular
Baghouse, You Need To Know The The Diameter Of Bag (D), Length Of Bags (L),
And Number Of Bags (N):
 The formula is: D x 3.142 = A
 A div 12 = B
 B x L = SF (sq. ft. per bag)
 SF x N = total sq. ft. of cloth in baghouse
To Find Air To Cloth Ratio (Should Be 5.1 To 1 In Batch, And 5.5 To 1 In Drum Plants)
 Determine square footage of an individual bag (X)
 Multiply that by the number of bags (Y)
 Divide that answer by baghouse CFM (Z). X times Y = total square feet of cloth (sq/ft). Z divide sq/ft = air to cloth ratio
Most manufacturers figure drum air velocity at between 900 & 1000 FPM.
.
CONVEYORS
To Find The Speed Of The Conveyor:
 Calculate the sheave ratio, i.e.: 10" drive, 18" driven
 10 divided by 18 = .555 Multiply motor speed by the answer = input RPM
 Input RPM divided by gear box ratio x diameter of head pulley x .2618= belt speed in FPM
 Example: Assume an 1800 RPM motor, a 251 gear box and an 28" head pulley: 1800 x .555= 999 divide 25
= 39.96 x 28= 1118.88 x .2618= 292.92 FPM
To Zero Ramsey 10201 Belt Scales (Total Tons In Lifetime)
 Press: Setup  76  Enter
 1853  Enter  Enter
PUMPS
 HL225 .01898 gallons per revolution
 K225 .1055 gallons per revolution
 L225 .23 gallons per revolution
 2"Q34 .23 gallons per revolution
 3"Q34 .61 gallons per revolution
Please email us with your thoughts and/or
questions.Cliff  USA
cmconsulting@hotmail.com
Doug  Canada
dougbleackley@sasktel.net
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